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I’ll assume this means solve (i^(-4n+1) - i^(-4n-1))/2 = 0 let’s say j = i^(-4n-1) we can substitute j into the original equation and get ((i^2)j-j)/2 = 0 we can just multiply both sides by 2 and get rid of that denominator (i^2)j-j = 0 we can fac.

I4n+1. Depends on what is n. What is the value of (i 4n+1 - i 4n-1)/2. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more.

If n is not integer, it is a complicated question. Answered Aug 17, 18 by AbhishekAnand (86.9k points) selected Aug 17, 18 by Vikash Kumar. Where N is any integer Please help I really dont understand it.

Answer by ichudov(507) (Show Source):. You can put this solution on YOUR website!. If it is an integer, then i^4 is 1, and i^4n is one as well.

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